Guest guest Posted December 28, 2005 Report Share Posted December 28, 2005 Hello, The last time I calculated something like this, here's the information I used: The molar mass of magnesium phosphate is 262gr/mole based on the formula of Mg3(PO4)2. One mole = 6.02 x 1023 molecules. (superscripted 23) This is almost equivalent to a 12 X potency = or 1 part in 1,000,000,000,000,000,000,000,000 diluent (1 x 1024)(superscripted 24)A 6X potency is = 1 part in 1,000,000 diluent. So, my decimals may be a little off but my estimate would be 2.32 x 10-3 (superscripted) mcg.You chemistry and math folks, (and you know who you are), please correct my math and logic. I think the MD is just interested in comparing physiological doses --so maybe the information in the following articles might also be helpful. (Check, the ion and hormone concentrations --they are all greater than the homeopathic cell salt.) How Does Homeopathy Work ( Kratz, PharmD) www.tldp.com or info(@townsendletter.com)Homeopathy's Law of Infinitesimals ( Barrett, MD)at www.homeowatch.orgFor molar mass calculations just type in "molar mass" in your search engines! Benton, ND Battle Ground, WA.(General Practice) Quote Link to comment Share on other sites More sharing options...
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