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Homemade Lugol's recipes

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These recipes are from /Israel:

I make my own Lugol's original formula (5%). 85ml distilled water mixed

with 10g postassium iodide (KI), then add 5g iodine crystals(I). It will

need to set in a covered container to allow all the crystals to dissolve.

Dose equivalent is 6.25mg/drop (vertical) when the iodine is in solution.

You will need a scale to measure with. Water weighs one gram/ml. Storage

period is indefinite with a properly sealed glass bottle. Rubber stoppered

bottles typically deteriorate within a year.


Formula to make 5% Lugol's iodine one ounce batch:

2.84g KI

1.42g I

24.14ml HOH


Here is the method for making 5% Lugol's iodine (6.25 mg/drop) in a nutshell:

1. Obtain a clean, empty 1 quart container (with lid)

2. Fill about halfway with distilled water (RO water is also okay)

3. Put in 44 grams of elemental iodine crystal (you need a scale)

4. Stir with non-metal spoon (wood is okay).

5. Put in 88 grams of potassium iodide, and stir some more.

6. Fill jar to about 80% of capacity with distilled water.

7. Let it set overnight. If cap is metal, put waxed paper between it and

the jar; iodine attacks metal.

8. The next day, it is ready for use.


To prepare a 10% LUGOL'S SOLUTION, the ratios of the elements change

somewhat, since elemental iodine is not very soluble in water (it is more

soluble in alcohol). Thus, a higher percentage of KI is needed.

1. Put 118 ml (4 fl. oz.) of distilled water in a dark glass container.

2. Mix 33.7 grams (1.18 oz.) of potassium iodide into the solution prepared

in step one. Use a wooden or plastic spoon to stir--do not use metal! Stir

until completely mixed.

3. Add 16.9 grams of iodine crystals to the mix, being very careful not to

touch the iodine crystals--they can burn the skin. If you come into contact

with the iodine crystals, wash your hands immediately with plenty of water.

Stir with the wooden or plastic spoon, and cover with a non-metal cover.

Let it sit overnight.

In the morning, stir once more or shake the solution. You now have a 10%

Lugol's solution, which can be taken internally or externally. If you

choose to take the solution internally, note that the concentration is

approximately 25.5 mg/drop! (Assuming the drop size is such that 70 drops

make up 1 teaspoon).

Note that the iodine concentrations posted on www.altcancer.com are

non-standard; they are including the potassium iodide in the percent

calculation. The standard Lugol's solution of 5% means that there is 5%

elemental iodine in the solution and the iodide is not considered. However,

when you calculate the mg/drop of iodine, the iodide is taken into account.

To do this, note that iodide is 0.769 times the total KI present, the ratio

of atomic weights of iodine to potassium. Then, [i + KI(0.769)]/ml = the

concentration of iodine. So when the altcancer folks talk about 15%

Lugol's solution, it is really only about 7% according to conventional

calculations. Their products are good, including the iodine, but be aware

of the inflated percentages.

Proof that the 10% Lugols solution described above is truly 10%:

16.9 gr/(16.9 gr + 33.7 gr + 118 ml) = 0.10 or (10 %) A similar calculation

can be performed for the strong iodine tincture.


~~~ There is no way to peace; peace is the way ~~~~

--A.J. Muste

~~~ Why do men fight for their servitude as stubbornly as though it were

their salvation? ~~~~

--Gilles Deleuze

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Guest Roderick.j.Smith

I am not a chemist or even have a chemistry exam but do like things to be as simple as possible, do the figures quoted have a ratio to each other of 2:1? In the 5% solution it is 88 grams of potassium iodide and 44 grams of elemental iodine crystal (2:1) and in the 10% solution it is 33.7grams of potassium iodide and 16.9grams of Iodine (2:1) so as you can buy a 100 gram bottle of Potassium Iodide and a 50 gram bottle of Iodine crystals on ebay, to make either solution just change the amount of water you add to change the potency? Another way to view it is to multiply the figures by 3 ( 33.7 x 3 = 101.1 ) and ( 16.9 x 3 = 50.7 ) If the ratio is 2:1 then 'loosing' 1.1 and .7 is hardly much to worry over and you end up with 100 grams and 50 grams.

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