* ATTENTION: STEPHANIE, Re: Lugol's and Optimal Concentration!

[Guest guest]

You're welcome. The info on Lugol's is from the group files. J Crow's has the

chemical info but it's on the MSDS sheet, not on the main page for iodine. I

think the biggest issue for some folks with J. Crow is the cost.

Linn

> >

> > The chemical composition of Lugol's is:

> >

> > Iodine - 5%

> > KI - 10% (KI=Potassium Iodide which is 7.5 of IODIDE and 2.5 of POTASSIUM)

> > Distilled Water - 85%

> >

> > The 2 to 1 ratio for Lugol's and Iodoral is KI (Iodide AND Potassium) to

Iodine, which is what Dr. B's book states also.

> >

> > HOW MUCH IODINE IS IN LUGOL'S?

> >

> >

> > • 100 gm of Lugol's 5% Solution = 5 gm Iodine + 10 gm Potassium Iodide (KI)

+ 85 gm Distilled Water

> >

> > • Two drops of Lugol's = [approximately] 12.5 mg Iodine/Iodide

> >

> >

> > Explanation

> >

> > • 10 gm Potassium Iodide = [approximately] 7.5 gm Iodide + 2.5 gm Potassium

[For details, see below, " How much Iodide is in 10 grams of Potassium Iodide? " ]

> >

> > • 5 gm Iodine + 7.5 gm Iodide [from the Potassium Iodide] = 12.5 gm

Iodine/Iodide

> > o 12.5 gm Iodine/Iodide = 12,500 mg Iodine/Iodide

> > ß 1 gm (gram) = 1000 mg (milligrams)

> > ß 12.5 gm = 12,500 mg [multiply by 1000]

> >

> > • 100 gm Lugol's = 12,500 mg Iodine/Iodide

> >

> > • 1 gm Lugol's = 125 mg Iodine/Iodide [divide by 100]

> > o 1 gm = [approximately] 1 ml

> > o 1 ml Lugol's = 125 mg Iodine/Iodide

> >

> > • Two drops of Lugol's = 12.5 mg Iodine/Iodide

> > o 20 drops of an aqueous solution = [approximately] 1 ml

> > o 2 drops = 2/20 ml = 1/10 ml

> > o 1/10 x 125 mg = 12.5 mg

> >

> >

> > How much Iodide is in 10 grams of Potassium Iodide?

> >

> > To determine how much iodide is in Potassium Iodide, you find the atomic

weights for each on the periodic chart. Then add them together to determine the

total weight. You then figure out how much of the total weight that Iodine

accounts for.

> >

> > Atomic Weight of Potassium (K) = 39.1

> > Atomic Weight of Iodine (I) = 126.9

> > Total Atomic Weight KI = 166.0

> >

> > Iodide in 10 gm KI = 126.9/166 x 10 = 0.76 x 10 = 7.6 gm Iodide.

> > For simplicity, this is rounded down to 7.5 gm Iodide.

> >

> > I = Iodine

> > I(-) = Iodide = Iodine with an extra electron, resulting in a negative

charge.

> >

> > Since the electron weighs almost nothing, both Iodine and Iodide have an

atomic weight of 126.9.

> >

> > KI = Potassium Iodide

> >

> > Hope this helps.

> >

> > Linn

>