Guest guest Posted July 21, 2006 Report Share Posted July 21, 2006 The question reads: An order calls for D10W/0.45% NaCl IV to run at 40 mL/hr. You have 1L of D10W and a vial of NaCl (4 mEq/mL) available. How would you prepare this bottle?? If someone could help me out I have had the toughest time on this problem. Thanks. Quote Link to comment Share on other sites More sharing options...
Guest guest Posted July 21, 2006 Report Share Posted July 21, 2006 Multiply 24hr/day x 40 ml / hr = number of ml per day needed of D10w/0.45%NaCl. Divide that number by 1000 ml / bag that tells you the number of IVs needed in one day. 960 ml per day which is close to 1000 ml or one liter NO amount of NaCL is ordered in addition to the D10W. Giving you the information on a vial of NaCl is extra informatiom and is to 'trick you' . However you may have left this part of the problem out. If you did it might look like this: " " An order calls for D10W/0.45% NaCl + NaCl 8mEq IV to run at 40 mL/hr. You have 1L of D10W and a vial of NaCl (4 mEq/mL) available. How would you prepare this bottle?? " " " If this were the case you would need one liter of D10W/0.45%NaCl and then add 2 ml of NaCl electrolyte. Set up a Ratio/Proportion: 4 meq/1ml = 8meq/X ml Solve: 1x8/4 = 2 ml Preparation: Using ONE 3 ml syringe withdraw 2 ml of NaCl (4mEq/ml) and inject into a 1 L D10W/0.45% NaCl sloution. Mix well. Label and dispense to the nursing department. It is my suspicion that you did not include the amount of NaCl in your problem. But if what you wrote is correct then the preparation would simply be to : Label the 1L of D10W/0.45% NaCl correctly. Hope this helps. Respectfully, Jeaneta Mastron CPht BS Founder/Owner The question reads: An order calls for D10W/0.45% NaCl IV to run at 40 mL/hr. You have 1L of D10W and a vial of NaCl (4 mEq/mL) available. How would you prepare this bottle?? If someone could help me out I have had the toughest time on this problem. Thanks. Quote Link to comment Share on other sites More sharing options...
Guest guest Posted July 21, 2006 Report Share Posted July 21, 2006 Jeanetta LOOK AGAIN at the question: The question reads: An order calls for D10W/0.45% NaCl IV to run at 40 mL/hr. You have 1L of D10W and a vial of NaCl (4 mEq/mL) available. How would you prepare this bottle?? what you have is 1L of D10W and a vail of 4meq/ml NaCl. what you need is a bag of D10w/0.45% NaCl to run at 40ml/hr. the extra info is the rate. I would solve this by looking at a bag of NS or 0.45% saline and seeing how many meq's per ml and go from there. but this person is probably not in a pharmacy and working from a book. I too have issues setting problems up. once i do so i can solve it easily. how would we set this up? --- Jeanetta Mastron <rxjm2002@...> wrote: Multiply 24hr/day x 40 ml / hr = number of ml per day needed of D10w/0.45%NaCl. Divide that number by 1000 ml / bag that tells you the number of IVs needed in one day. 960 ml per day which is close to 1000 ml or one liter. NO amount of NaCL is ordered in addition to the D10W. Giving you the information on a vial of NaCl > is extra informatiom and is to 'trick you' . > > However you may have left this part of the problem > out. If you did it might look like this: > " " An order calls for D10W/0.45% NaCl + NaCl 8mEq > IV to run at 40 mL/hr. You have > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > How would you > prepare this bottle?? " " " > > If this were the case you would need one liter of > D10W/0.45%NaCl and then add 2 ml of NaCl > electrolyte. > > Set up a Ratio/Proportion: > > 4 meq/1ml = 8meq/X ml > Solve: > > 1x8/4 = 2 ml > > Preparation: Using ONE 3 ml syringe withdraw 2 ml > of NaCl (4mEq/ml) and inject into a 1 L D10W/0.45% > NaCl sloution. Mix well. Label and dispense to the > nursing department. > > It is my suspicion that you did not include the > amount of NaCl in your problem. > But if what you wrote is correct then the > preparation would simply be to : > Label the 1L of D10W/0.45% NaCl correctly. > > Hope this helps. > > > Respectfully, > Jeaneta Mastron CPht BS > Founder/Owner > > > > > > The question reads: > > An order calls for D10W/0.45% NaCl IV to run at 40 > mL/hr. You have > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > How would you > prepare this bottle?? > > If someone could help me out I have had the toughest > time on this > problem. Thanks. > > > > > > > [Non-text portions of this message have been > removed] > > " If the world were perfect, it wouldn't be. " - Yogi Berra ONLY AFTER YOU'VE LOST EVERYTHING ARE YOU FREE TO DO ANYTHING if you have the time to click on an e-mail link like this one: http://www.sendmoreinfo.com/ID/2425657 you really can earn some extra cash! __________________________________________________ Quote Link to comment Share on other sites More sharing options...
Guest guest Posted July 22, 2006 Report Share Posted July 22, 2006 You are correct Karin I mis-read the problem! I kept reading it as 'you have lL of D10W/0.45% NaCl and 1 vial of NaCl (4mEq/1ml) available " . It actually says: " you have lL of D10W and 1 vial of NaCl (4mEq/1ml) available " . No need to find the bag at work. You can figure this out at home with a calculator. Okay here is how to make it: Problem: How much NaCl (4mEq/ml) should be added to 1L of D10W to make 1L D10W/0.45%? Fact: 1 Liter of Normal Saline has 0.9% has 154 meq of NaCl Use Logic and Ratio/Proportion: Since 0.9% is 0.9 grams/100 ml, then 9 grams of NaCl is in 1000 ml. Or can be stated as: 9grams NaCl/1L NS Since 0.45 % 0. 45 grams / 100 ml, 4.5 grams are in 1000 ml of solution. Now since 1L of 0.9% = 154 mEq NaCl 1 L of 0.45% of NaCl = 77 mEq, because it is ½ the strength of 0.9% Since the vial has 4mEq/ml, then 77mEq = 19.25 ml of NaCl Therefore: 1L D10W/0.45% NaCl is equal to 100grams of Dextrose, 4.5 grams of NaCl, and 77 mEq NaCl To make this LVP: Withdraw 19.25 ml from a 10 ml vial of NaCl (4mEq/ml) and inject it into a 1L bag of D10W, mix well and label. I do teach this in my classroom in a module called Drug Distribution. This calculation is used when you run out of the L with the mixture that you would like or need. It can be used by small hospitals that do not stock all available solutions. However in 'today's' world being out of stock rarely happens and larger hospitals will stock all available solution strengths and combination strengths. Hope this helps you out. I really doubt that this would be on the PTCB exam. But I would like to see it on an exam for an IV Specialist Certification if and when one comes to exist. Respectfully, Jeanetta Mastron CPhT BS Founder/Owner > Multiply 24hr/day x 40 ml / hr = number of ml per day > needed of D10w/0.45%NaCl. Divide that number by > 1000 ml / bag that tells you the number of IVs needed > in one day. 960 ml per day which is close to 1000 ml > or one liter. NO amount of NaCL is ordered in > addition to the D10W. Giving you the information on a > vial of NaCl > > is extra informatiom and is to 'trick you' . > > > > However you may have left this part of the problem > > out. If you did it might look like this: > > " " An order calls for D10W/0.45% NaCl + NaCl 8mEq > > IV to run at 40 mL/hr. You have > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > How would you > > prepare this bottle?? " " " > > > > If this were the case you would need one liter of > > D10W/0.45%NaCl and then add 2 ml of NaCl > > electrolyte. > > > > Set up a Ratio/Proportion: > > > > 4 meq/1ml = 8meq/X ml > > Solve: > > > > 1x8/4 = 2 ml > > > > Preparation: Using ONE 3 ml syringe withdraw 2 ml > > of NaCl (4mEq/ml) and inject into a 1 L D10W/0.45% > > NaCl sloution. Mix well. Label and dispense to the > > nursing department. > > > > It is my suspicion that you did not include the > > amount of NaCl in your problem. > > But if what you wrote is correct then the > > preparation would simply be to : > > Label the 1L of D10W/0.45% NaCl correctly. > > > > Hope this helps. > > > > > > Respectfully, > > Jeaneta Mastron CPht BS > > Founder/Owner > > > > > > > > > > > > The question reads: > > > > An order calls for D10W/0.45% NaCl IV to run at 40 > > mL/hr. You have > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > How would you > > prepare this bottle?? > > > > If someone could help me out I have had the toughest > > time on this > > problem. Thanks. > > > > > > > > > > > > > > [Non-text portions of this message have been > > removed] > > > > > > > " If the world were perfect, it wouldn't be. " > - Yogi Berra > > ONLY AFTER YOU'VE LOST EVERYTHING ARE YOU FREE TO DO ANYTHING > > if you have the time to click on an e-mail link like this one: http://www.sendmoreinfo.com/ID/2425657 you really can earn some extra cash! > > __________________________________________________ > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted July 22, 2006 Report Share Posted July 22, 2006 Thanks so much for showing me how that problem worked out. I had the darnest time with it. -- In , " Jeanetta Mastron CPhT BS Chemistry " <rxjm2002@...> wrote: > > > You are correct Karin I mis-read the problem! I kept reading it as > 'you have lL of D10W/0.45% NaCl and 1 vial of NaCl (4mEq/1ml) available " . > > It actually says: " you have lL of D10W and 1 vial of NaCl (4mEq/1ml) > available " . > > No need to find the bag at work. You can figure this out at home with > a calculator. > > Okay here is how to make it: > > > Problem: > How much NaCl (4mEq/ml) should be added to 1L of D10W to make 1L > D10W/0.45%? > > > Fact: > 1 Liter of Normal Saline has 0.9% has 154 meq of NaCl > > Use Logic and Ratio/Proportion: > > Since 0.9% is 0.9 grams/100 ml, then 9 grams of NaCl is in 1000 ml. > Or can be stated as: 9grams > NaCl/1L NS > > Since 0.45 % 0. 45 grams / 100 ml, 4.5 grams are in 1000 ml of solution. > > Now since 1L of 0.9% = 154 mEq NaCl > 1 L of 0.45% of NaCl = 77 mEq, because it is ½ the strength of 0.9% > > Since the vial has 4mEq/ml, then 77mEq = 19.25 ml of NaCl > > Therefore: 1L D10W/0.45% NaCl is equal to > 100grams of Dextrose, 4.5 grams of NaCl, and 77 mEq NaCl > > To make this LVP: > Withdraw 19.25 ml from a 10 ml vial of NaCl (4mEq/ml) and inject it > into a 1L bag of D10W, mix well and label. > > > I do teach this in my classroom in a module called Drug Distribution. > This calculation is used when you run out of the L with the mixture > that you would like or need. It can be used by small hospitals that do > not stock all available solutions. However in 'today's' world being > out of stock rarely happens and larger hospitals will stock all > available solution strengths and combination strengths. > > > Hope this helps you out. I really doubt that this would be on the PTCB > exam. But I would like to see it on an exam for an IV Specialist > Certification if and when one comes to exist. > > Respectfully, > Jeanetta Mastron CPhT BS > Founder/Owner > > > > > > Multiply 24hr/day x 40 ml / hr = number of ml per day > > needed of D10w/0.45%NaCl. Divide that number by > > 1000 ml / bag that tells you the number of IVs needed > > in one day. 960 ml per day which is close to 1000 ml > > or one liter. NO amount of NaCL is ordered in > > addition to the D10W. Giving you the information on a > > vial of NaCl > > > is extra informatiom and is to 'trick you' . > > > > > > However you may have left this part of the problem > > > out. If you did it might look like this: > > > " " An order calls for D10W/0.45% NaCl + NaCl 8mEq > > > IV to run at 40 mL/hr. You have > > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > > How would you > > > prepare this bottle?? " " " > > > > > > If this were the case you would need one liter of > > > D10W/0.45%NaCl and then add 2 ml of NaCl > > > electrolyte. > > > > > > Set up a Ratio/Proportion: > > > > > > 4 meq/1ml = 8meq/X ml > > > Solve: > > > > > > 1x8/4 = 2 ml > > > > > > Preparation: Using ONE 3 ml syringe withdraw 2 ml > > > of NaCl (4mEq/ml) and inject into a 1 L D10W/0.45% > > > NaCl sloution. Mix well. Label and dispense to the > > > nursing department. > > > > > > It is my suspicion that you did not include the > > > amount of NaCl in your problem. > > > But if what you wrote is correct then the > > > preparation would simply be to : > > > Label the 1L of D10W/0.45% NaCl correctly. > > > > > > Hope this helps. > > > > > > > > > Respectfully, > > > Jeaneta Mastron CPht BS > > > Founder/Owner > > > > > > > > > > > > > > > > > > The question reads: > > > > > > An order calls for D10W/0.45% NaCl IV to run at 40 > > > mL/hr. You have > > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > > How would you > > > prepare this bottle?? > > > > > > If someone could help me out I have had the toughest > > > time on this > > > problem. Thanks. > > > > > > > > > > > > > > > > > > > > > [Non-text portions of this message have been > > > removed] > > > > > > > > > > > > " If the world were perfect, it wouldn't be. " > > - Yogi Berra > > > > ONLY AFTER YOU'VE LOST EVERYTHING ARE YOU FREE TO DO ANYTHING > > > > if you have the time to click on an e-mail link like this one: > http://www.sendmoreinfo.com/ID/2425657 you really can earn some extra > cash! > > > > __________________________________________________ > > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted July 22, 2006 Report Share Posted July 22, 2006 Glad to be of help Joe2weatherman! If you are taking the exam today please let us know how you think you did! If not, I look forward to helping you with more of your study questions. Jeanetta joe2weatherman <joe2weatherman@...> wrote: Thanks so much for showing me how that problem worked out. I had the darnest time with it. -- In , " Jeanetta Mastron CPhT BS Chemistry " <rxjm2002@...> wrote: > > > You are correct Karin I mis-read the problem! I kept reading it as > 'you have lL of D10W/0.45% NaCl and 1 vial of NaCl (4mEq/1ml) available " . > > It actually says: " you have lL of D10W and 1 vial of NaCl (4mEq/1ml) > available " . > > No need to find the bag at work. You can figure this out at home with > a calculator. > > Okay here is how to make it: > > > Problem: > How much NaCl (4mEq/ml) should be added to 1L of D10W to make 1L > D10W/0.45%? > > > Fact: > 1 Liter of Normal Saline has 0.9% has 154 meq of NaCl > > Use Logic and Ratio/Proportion: > > Since 0.9% is 0.9 grams/100 ml, then 9 grams of NaCl is in 1000 ml. > Or can be stated as: 9grams > NaCl/1L NS > > Since 0.45 % 0. 45 grams / 100 ml, 4.5 grams are in 1000 ml of solution. > > Now since 1L of 0.9% = 154 mEq NaCl > 1 L of 0.45% of NaCl = 77 mEq, because it is � the strength of 0.9% > > Since the vial has 4mEq/ml, then 77mEq = 19.25 ml of NaCl > > Therefore: 1L D10W/0.45% NaCl is equal to > 100grams of Dextrose, 4.5 grams of NaCl, and 77 mEq NaCl > > To make this LVP: > Withdraw 19.25 ml from a 10 ml vial of NaCl (4mEq/ml) and inject it > into a 1L bag of D10W, mix well and label. > > > I do teach this in my classroom in a module called Drug Distribution. > This calculation is used when you run out of the L with the mixture > that you would like or need. It can be used by small hospitals that do > not stock all available solutions. However in 'today's' world being > out of stock rarely happens and larger hospitals will stock all > available solution strengths and combination strengths. > > > Hope this helps you out. I really doubt that this would be on the PTCB > exam. But I would like to see it on an exam for an IV Specialist > Certification if and when one comes to exist. > > Respectfully, > Jeanetta Mastron CPhT BS > Founder/Owner > > > > > > Multiply 24hr/day x 40 ml / hr = number of ml per day > > needed of D10w/0.45%NaCl. Divide that number by > > 1000 ml / bag that tells you the number of IVs needed > > in one day. 960 ml per day which is close to 1000 ml > > or one liter. NO amount of NaCL is ordered in > > addition to the D10W. Giving you the information on a > > vial of NaCl > > > is extra informatiom and is to 'trick you' . > > > > > > However you may have left this part of the problem > > > out. If you did it might look like this: > > > " " An order calls for D10W/0.45% NaCl + NaCl 8mEq > > > IV to run at 40 mL/hr. You have > > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > > How would you > > > prepare this bottle?? " " " > > > > > > If this were the case you would need one liter of > > > D10W/0.45%NaCl and then add 2 ml of NaCl > > > electrolyte. > > > > > > Set up a Ratio/Proportion: > > > > > > 4 meq/1ml = 8meq/X ml > > > Solve: > > > > > > 1x8/4 = 2 ml > > > > > > Preparation: Using ONE 3 ml syringe withdraw 2 ml > > > of NaCl (4mEq/ml) and inject into a 1 L D10W/0.45% > > > NaCl sloution. Mix well. Label and dispense to the > > > nursing department. > > > > > > It is my suspicion that you did not include the > > > amount of NaCl in your problem. > > > But if what you wrote is correct then the > > > preparation would simply be to : > > > Label the 1L of D10W/0.45% NaCl correctly. > > > > > > Hope this helps. > > > > > > > > > Respectfully, > > > Jeaneta Mastron CPht BS > > > Founder/Owner > > > > > > > > > > > > > > > > > > The question reads: > > > > > > An order calls for D10W/0.45% NaCl IV to run at 40 > > > mL/hr. You have > > > 1L of D10W and a vial of NaCl (4 mEq/mL) available. > > > How would you > > > prepare this bottle?? > > > > > > If someone could help me out I have had the toughest > > > time on this > > > problem. Thanks. > > > > > > > > > > > > > > > > > > > > > [Non-text portions of this message have been > > > removed] > > > > > > > > > > > > " If the world were perfect, it wouldn't be. " > > - Yogi Berra > > > > ONLY AFTER YOU'VE LOST EVERYTHING ARE YOU FREE TO DO ANYTHING > > > > if you have the time to click on an e-mail link like this one: > http://www.sendmoreinfo.com/ID/2425657 you really can earn some extra > cash! > > > > __________________________________________________ > > Quote Link to comment Share on other sites More sharing options...
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